TIPS FOR CHEMISTRY PAPER 5
When
asked to draw a diagram, ALWAYS mention the volume of the apparatus being used.
The one most often used is gas syringe. It is better to limit the
volume of syringe to less than 500 cm3 . Also, the volume of a commonly used
small test tube is around 16 cm3 and that of a boiling tube is about 25 cm3, volume of beaker 250cm3, conical flask 100cm3 and burette 50cm3.
We
always have to keep the volume of the apparatus we are using while choosing the
volume of the solution for the planning. Saying that we are going to place
50cm3 of aqueous HCl in a test tube is of course not going to please the
examiners.However, we can use greater volume if we state that the
volume of the beaker is 400cm3 or 500 cm3 or so on. So, stating the volume of
the apparatus is very very important
Always
while measuring volume of solutions, use burette or pipette because they have
low PERCENTAGE error. The question of percentage errors are usually asked in
P5. The percentage error becomes very unacceptable if we are measuring SMALL
volumes of solution or small masses. So, a 3dp balance is much better for
measuring masses than a 2dp balance as it would have much less % error when
small masses are being measured
While heating crystals strongly, do not use a simple test tube or any apparatus
with sharp edges as they are liable to crack at the sharp edges. For very
strong heating to a constant mass, a crucible placed on a pipe clay triangle is
appropriate. And of course to measure the mass of the crucible + solid, you
would have to place it on a balance. But we wouldn't want to fry our poor
balance by placing a very hot crucible on top of it. So, allow the crucible to
cool for a few minutes by placing it on a heat mat.
When
using a magnesium ribbon or any dirty surface, clean it with SANDPAPER
How
to prepare crystals (which is also linked with solubility)
So, we have to prepare a saturated solution first:
1. Take a fixed volume of water in a beaker of appropriate volume
2. Add the crystal to the water and stir continuously. You have to allow some time for the crystal to dissolve as it is an equilibrium process
3. After 5 min of stirring , if no solid crystals appear, add further mass of crystal
4. And repeat the process until solid appears in the beaker
5. Filter the solution using a filter paper and funnel so that the saturated solution is collected in a beaker(whose mass has been measured previously) beneath the funnel
Now we have a saturated solution in a beaker.
How to get the crystals:
1. We have to place the beaker in a warm water bath. We could use a burner as well but there is a risk of overheating the solution which could decompose the crystal. If the heat is appropriate, the water of the solution should evaporate and we should have dry crystals ready.
How to measure solubility:
6. Measure the mass of beaker + solution from step 5
7. Subtract the mass of beaker from the mass in 6 to get the mass of saturated solution
8. And evaporate as shown above to get the mass of crystals.
8. Measure the mass of crystal + beaker
9. Subtract mass of beaker from mass in 8 to get the mass of crystals
10. Subtract the mass of crystals from the mass of saturated solution to get the mass of water in the solution
11. I have assumed that all the masses are in grams. So, to get the solubility: Mass of crystal x 100/Mass of water
So, we have to prepare a saturated solution first:
1. Take a fixed volume of water in a beaker of appropriate volume
2. Add the crystal to the water and stir continuously. You have to allow some time for the crystal to dissolve as it is an equilibrium process
3. After 5 min of stirring , if no solid crystals appear, add further mass of crystal
4. And repeat the process until solid appears in the beaker
5. Filter the solution using a filter paper and funnel so that the saturated solution is collected in a beaker(whose mass has been measured previously) beneath the funnel
Now we have a saturated solution in a beaker.
How to get the crystals:
1. We have to place the beaker in a warm water bath. We could use a burner as well but there is a risk of overheating the solution which could decompose the crystal. If the heat is appropriate, the water of the solution should evaporate and we should have dry crystals ready.
How to measure solubility:
6. Measure the mass of beaker + solution from step 5
7. Subtract the mass of beaker from the mass in 6 to get the mass of saturated solution
8. And evaporate as shown above to get the mass of crystals.
8. Measure the mass of crystal + beaker
9. Subtract mass of beaker from mass in 8 to get the mass of crystals
10. Subtract the mass of crystals from the mass of saturated solution to get the mass of water in the solution
11. I have assumed that all the masses are in grams. So, to get the solubility: Mass of crystal x 100/Mass of water
When
you have to remove moisture from :
1. Surface:
Wash the surface with a stream of propanone. The water gets dissolved in the propanone and repeat it multiple times. Then gently heat the surface to evaporate the propanone from the surface
2. Vapour:
Use dessicants such as:
1. ANHYDROUS sulphuric acid
2. ANHYDROUS calcium chloride
3. Silica gel
You have to pass the vapour from the beaker containing the dessicant
Also, a useful property of soda lime is that it absorbs BOTH water vapour and carbon dioxide
1. Surface:
Wash the surface with a stream of propanone. The water gets dissolved in the propanone and repeat it multiple times. Then gently heat the surface to evaporate the propanone from the surface
2. Vapour:
Use dessicants such as:
1. ANHYDROUS sulphuric acid
2. ANHYDROUS calcium chloride
3. Silica gel
You have to pass the vapour from the beaker containing the dessicant
Also, a useful property of soda lime is that it absorbs BOTH water vapour and carbon dioxide
We
are also regularly asked to measure enthalpy changes
We use a plastic cup and thermometer for this purpose, however this has many disadvantages (asked regularly) and here are some of them with the required measures:
1. Heat loss to the surroundings from the beaker:
To avoid this:
a. Cover the plastic cup with a lid
b. Place the cup in a beaker. The air in the beaker acts a good insulator.
c. Use multiple cups so as to thicken the lateral layer of plastic
2. Instability of the cup
a. Place the cup in a glass beaker
3. For exothermic reactions, spray of the solution very likely
a. Use a large beaker to carry out the experiment rather than the small plastic cup (which has a small volume)
b. Put a lid on the top of the beaker (this only MINIMISES the spray, doesn't prevent it totally)
4. When we are heating a volume of water in glass beaker, there are two cases of heat loss to consider:
a. Heat loss from the beaker of water
b. Heat loss from the burner heating the volume of water
We use a plastic cup and thermometer for this purpose, however this has many disadvantages (asked regularly) and here are some of them with the required measures:
1. Heat loss to the surroundings from the beaker:
To avoid this:
a. Cover the plastic cup with a lid
b. Place the cup in a beaker. The air in the beaker acts a good insulator.
c. Use multiple cups so as to thicken the lateral layer of plastic
2. Instability of the cup
a. Place the cup in a glass beaker
3. For exothermic reactions, spray of the solution very likely
a. Use a large beaker to carry out the experiment rather than the small plastic cup (which has a small volume)
b. Put a lid on the top of the beaker (this only MINIMISES the spray, doesn't prevent it totally)
4. When we are heating a volume of water in glass beaker, there are two cases of heat loss to consider:
a. Heat loss from the beaker of water
b. Heat loss from the burner heating the volume of water
Titration
is accurate because:
1. Standard solution of acid/base is used
2. we obtain concordant titres
3. % error in pipette and burette is very small
4. The end point of a titration is sharp
1. Standard solution of acid/base is used
2. we obtain concordant titres
3. % error in pipette and burette is very small
4. The end point of a titration is sharp
We
do not need to measure the mass of a reagent or volume of reagent that is in
excess
If
the percentage difference between the measured value and the true value is more
than the maximum apparatus error, this means the ex foperimenter's technique
needs modification. If not, the error could be considered to be entirely due to
the intrinsic error or the apparatus used
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