The direction of an electric field is defined as the direction in which
a positive charge would move if it were free to do so
The electric field strength E, is
defined as the force per unit charge acting on a small positive charge placed at that
point,
i.e.
E = F/Q N C-1
The force between charges
according to coulomb is
proportional to the product of the charges and inversely proportional
to the square of the distance between them
i.e F = kQ1Q2/r2
where k is a
constant of proportionality, the value of which depends on the medium around
the charges
•
this law applies
to point charges but can
be used for charged spheres provided
their radii are small compared to their separation
The potential difference VAB between
two points A and B in an electric field is the work done W, in moving a unit positive charge from B of lower potential to A of higher
potential against the direction of the line of action of the force on the unit
charge.
That
is VAB = W/Q i.e.
W = VQ SI unit of V is Volts
But
also, work done (which is energy)
W =
Fd, therefore Fd = VQ with units of V C
·
Rearranging,
F/Q = V/d,
·
but
F/Q is the force per unit charge which is the definition of electric field
strength E.
·
Hence
for a uniform field, the field strength E = V/d V m-1
·
E
has 2 equivalent SI units, V m-1 = N C-1
From Coulomb’s Law, the
force on a test charge Q1,
a distance r from the
isolated point charge Q2
is given by,
F = kQ1Q2/r2
The electric field E at the
location of the test charge q, is given by
E
= F/q
Therefore the electric field due to the isolated point charge is
F = kQ1Q2/r2
Electric field has been
defined as the force per unit charge
Electric potential V, at a
point in an electric field is defined as the work done or potential energy PE,
in bringing unit positive charge from infinity to the point
i.e V = PE/Q
The field strength is equal
to the negative of the potential gradient at that point
V = PE/Q = (F x r)/q = (kQ1Q2/r2x
r)/q = kQ/r
where k = 1/4πε0r
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