Tuesday 15 November 2016

Physics - Revision Notes on Electric Fields

Electric field is a region in space where a stationary charge experiences a force
The direction of an electric field is defined as the direction in which a positive charge would move if it were free to do so
The electric field strength E, is defined as the force per unit charge acting on a small positive charge placed at that point,
 i.e.     E = F/Q  N C-1

The force between charges according to coulomb is
proportional to the product of the charges and inversely proportional to the square of the distance between them
 i.e F = kQ1Q2/r2
  where k is a constant of proportionality, the value of which depends on the medium around the charges
             this law applies to point charges but can be used for charged spheres provided their radii are small compared to their separation

The potential difference VAB between two points A and B in an electric field is the work done W, in moving a unit positive charge from B of lower potential to A of higher potential against the direction of the line of action of the force on the unit charge.
That is VAB = W/Q   i.e.  W = VQ   SI unit of V is Volts
But also, work done (which is energy)
W = Fd, therefore Fd = VQ with units of V C

·           Rearranging, F/Q = V/d,
·           but F/Q is the force per unit charge which is the definition of electric field strength E.
·           Hence for a uniform field, the field strength E = V/d V m-1
·           E has 2 equivalent SI units, V m-1 = N C-1

From Coulomb’s Law, the force on a test charge Q1, a distance r from the isolated point charge Q2 is given by,
F = kQ1Q2/r2
The electric field E at the location of the test charge q, is given by
 E = F/q
Therefore the electric field due to the isolated point charge is
 F = kQ1Q2/r2

Electric field has been defined as the force per unit charge
Electric potential V, at a point in an electric field is defined as the work done or potential energy PE, in bringing unit positive charge from infinity to the point
 i.e V = PE/Q

The field strength is equal to the negative of the potential gradient at that point
V = PE/Q = (F x r)/q = (kQ1Q2/r2x r)/q   = kQ/r 
            where k = 1/4πε0r


Please Comment and questions or suggestions, Like and Share.
Thank you. 

No comments:

Post a Comment